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Pythagoras²Equation Solver
Navigationa² + b² = c²
Motore Cartesiano 2Dd = √(Δx² + Δy²)

Risolutore Distanza e Punto Medio

Plot any two points (x₁, y₁) and (x₂, y₂) on the Cartesian plane to compute exact radical distance, midpoint, slope, and inclination angle. Looking for standard triangle side lengths or inverse trigonometry? Visit our root Pythagoras equation solver.

Interactive SVG Coordinate GridSimplified Exact RadicalsMidpoint, Slope & Angle
Result updated: Distance is 2radical 13, approximately 7.2111, midpoint is (3, 5).

Risolutore Distanza e Punto Medio

d = √((x₂ - x₁)² + (y₂ - y₁)²) · M = ((x₁ + x₂)/2, (y₁ + y₂)/2)

Punto 1 (x₁, y₁)
Enter finite coordinate numbers including negatives or decimals.
Punto 2 (x₂, y₂)
Esempi Rapidi
Distanza Esatta
2√13
√52
Lunghezza Decimale
7.211103
dx=4, dy=6
Punto Medio (M)
(3, 5)
Pendenza & Inclinazione
3/2 (56.31°)
024602468dx=4dy=6d=2√13P₁(1,2)P₂(5,8)

Derivazione Pitagorica

1. Map Horizontal & Vertical Leg Lengths (dx, dy)
dx = |5 - 1| = 4, dy = |8 - 2| = 6
a = 4, b = 6
2. Apply the Pythagorean Sum of Squares
d² = 4² + 6²
d² = 16 + 36 = 52
3. Extract Exact Radical & Decimal Hypotenuse
d = √52
d = 2√13 ≈ 7.2111
4. Compute Midpoint & Slope
M = ((1 + 5)/2, (2 + 8)/2)
M = (3, 5), m = 3/2

Come la Formula della Distanza Usa a² + b² = c²

Every non-vertical, non-horizontal segment between two points forms the hypotenuse c of an invisible right triangle whose horizontal run is a = dx = |x₂ - x₁| and whose vertical rise is b = dy = |y₂ - y₁|.

a² + b² = c² ⟹ (|x₂ - x₁|)² + (|y₂ - y₁|)² = d² ⟹ d = √((x₂ - x₁)² + (y₂ - y₁)²)